Find the digit for A in
6 1 A
+1 A 5
______
8 0 3
8
Consider the ones digits:
A + 5 = 3 which means when 5 is added to A, it is = a number with 3 in its ones place. Here, A is a number between 0 to 9.
We know that 8 + 5 = 13, so A could be equal to 8.
Consider the tens digits, 1 + A = 0
If A = 8, then 1 + 8 + 1(carried over) = 10
Hundreds digits, 6 + 1 + 1(carried over) = 8
6 1 8
+1 8 5
______
8 0 3
Hence, A = 8