Find the digits A and B for the given multiplication to hold true.
$\begin{matrix} A A \times B B A A = A A 0 A 6 A \end{matrix}$

A = 3, B = 1

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A = 4, B = 5

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A = 6, B = 2

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A = 2, B = 6

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Solution

The correct option is A
A = 3, B = 1

From the given multiplication we can deduce,

A + A = 6
2A = 6;
A = 3
Also, A x B = A. This is possible only if B = 1
Hence A = 3 and B = 1

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Find the digits A and B for the given multiplication to hold true.
$\begin{matrix} A A \times B B A A = A A 0 A 6 A \end{matrix}$

$\begin{matrix} A A \times B B A A A A A 6 A \end{matrix}$
A=___; B=____

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