Question

Find the dimensions of $\frac{E}{B}$. (E = Electric field , B = Magnetic field)

Answer 1

Dimension of $F=ML{T}^{-2}$

and $F=qE$

Dimension of $E=\frac{F}{q}=\frac{ML{T}^{-2}}{AT}$

$=M{A}^{-1}L{T}^{-3}$

Now, $F=ilB$

$B=\frac{F}{il}$

Dimension of $B=\frac{ML{T}^{-2}}{A\times L}=M{A}^{-1}{T}^{-2}$

So, dimension of $\frac{E}{B}=\frac{M{A}^{-1}L{T}^{-3}}{M{A}^{-1}{T}^{-2}}$

$=L{T}^{-1}$