Find the dimensions of electricity permittivity.

[A^{2} M^{- 1} L^{- 3} T^{4}]

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[A^{2} M^{- 1} L^{- 3} T^{0}]

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[A M^{- 1} L^{- 3} T^{4}]

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[A^{2} M^{0} L^{- 3} T^{4}]

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Solution

The correct option is A $[A^{2} M^{- 1} L^{- 3} T^{4}]$
Electrostatic force acting between the charges $F = \frac{q_{1} q_{2}}{4 π ϵ_{o} r^{2}}$
$⟹$ $ϵ_{o} = \frac{q_{1} q_{2}}{4 π F r^{2}}$
Dimensions of electricity permeability $ϵ_{o} = \frac{[A T] [A T]}{[M L T^{- 2}] [L]^{2}}$
$⟹$ $ϵ_{o} = [A^{2} M^{- 1} L^{- 3} T^{4}]$

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Similar questions

\frac{1}{ϵ_{0}} \frac{e^{2}}{h c}

ϵ_{0}

When we divide $3 t^{4} + 5 t^{3} - 7 t^{2} + 2 t + 2$ by $t^{2} + 3 t + 1$ , we get $3 t^{2} - 4 t + 2$ .

T_{n} = {sin}^{n} x + {cos}^{n} x

2 T_{6} - 3 T_{4} + 10.

T_{n} θ + c o s^{n} θ

2 T_{6} - 3 T_{4} + 1 = 0

M^{- 1} L^{- 2} T^{3} θ^{1}

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