Find the direction cosines of the unit vector perpendicular to the plane $\to r . (6^i - 3^j - 2^k) + 1 = 0$

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Solution

Direction ratioes: $(6, - 3, - 2)$
Hence Directions cosines will be: $(\frac{6}{\sqrt{6^{2} + (- 3)^{2} + (- 2)^{2}}}, \frac{- 3}{\sqrt{6^{2} + (- 3)^{2} + (- 2)^{2}}}, \frac{- 2}{\sqrt{6^{2} + (- 3)^{2} + (- 2)^{2}}})$
$= (\frac{6}{7}, \frac{- 3}{7}, \frac{- 2}{7})$ Ans.

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