Find the direction cosines of vector →r which is equally inclined to OX,OY and OZ. Find total number of such vectors.
±1√3,±1√3,±1√3;8
Let l,m,n be the direction cosines of →r.
Since →r is equally inclined with x,y and z axis, l=m=n
∴l2+m2+n2⇒3l3=1⇒l=±1√3
∴ direction cosines of →r are ±1√3,±1√3,±1√3
Now, →r=∣∣→r∣∣(li+mj+nk)=→r=∣∣→r∣∣(±1√3i±1√3j±1√3k)
Since + and − signs can be arranged at three places,
⇒ there are eight vectors, i.e 2×2×2 which are equally inclined to axes.