Question

Find the direction ratio of the line $\frac{x-1}{2}=3y=\frac{2z+3}{4}$

Answer 1

Given equation of the line is $\frac{x-1}{2}=3y=\frac{2z+3}{4}$

$⟹\frac{x-1}{2}=\frac{y}{\frac{1}{3}}=\frac{2(z+\frac{3}{2})}{4}$

$⟹\frac{x-1}{2}=\frac{y}{1/3}=\frac{z+3/2}{2}$

The direction ratios of the line are $(2,1/3,2)$