Find the direction ratios of the plane 3-x-1-y-2-5-2z-3-1-

Simplify the given equation to find out the direction ratios of the plane.(3 x)/1=(y 2)/5=(2z 3)/10ex0ex⇒(x 3)/ 1=(y 2)/5=(z 3/2)/1/2Therefore, the direction ra ...

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Standard XIII

Mathematics

Equation of a Plane : Point Normal Form

Find the dire...

Question

Find the direction ratios of the plane $\frac{(3 - x)}{1} = \frac{(y - 2)}{5} = \frac{(2 z - 3)}{1}$ .

$1, 5, \frac{1}{2}$

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$- 1, 5, 1$

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$- 1, 5, \frac{1}{2}$

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$1, 5, 1$

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Solution

The correct option is C
$- 1, 5, \frac{1}{2}$

Simplify the given equation to find out the direction ratios of the plane.
$\frac{(3 - x)}{1} = \frac{(y - 2)}{5} = \frac{(2 z - 3)}{1} \Rightarrow \frac{(x - 3)}{- 1} = \frac{(y - 2)}{5} = \frac{(z - \frac{3}{2})}{\frac{1}{2}}$
Therefore, the direction ratio of the plane is $(- 1, 5, \frac{1}{2})$ .
Therefore, Option(C) is the correct answer.

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Find the direction ratios of the plane (3-x)1=(y-2)5=(2z-3)1.

The correct option is C -1,5,12Simplify the given equation to find out the direction ratios of the plane.(3-x)1=(y-2)5=(2z-3)1⇒(x-3)-1=(y-2)5=(z-32)12Therefore, the direction ratio of the plane is (-1,5,12).Therefore, Option(C) is the correct answer.

Find the direction ratios of the plane $\frac{(3 - x)}{1} = \frac{(y - 2)}{5} = \frac{(2 z - 3)}{1}$ .