Question

Find the discriminant for the following quadratic equation. Also, determine the nature of roots.
$3x^2-2\sqrt{6}x+2=0$

• A. D> 0; Roots are real
• B. D=0 ; Roots are real and equal
• C. D < 0 ; Roots are real
• D. D > 0; Roots are not real

Answer 1

The correct option is B D=0 ; Roots are real and equal

We have,
$3x^2-2\sqrt{6}x+2=0$
Comparing with $a{x}^2+bx+c=0,$ we get,
$a=3,b=-2\sqrt{6},c=2$
Discriminant, $D=b^2-4ac=24-24=0$
$\Rightarrow D=0$
So, roots are not real and equal
Hence, correct option is b.