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Discriminant

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Question

Find the discriminant of quadratic equation $x^{2} - 4 x + 1 = 0$ .

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Solution

Discriminant $= Δ = b^{2} - 4 a c$ where $a = 1, b = - 4, c = 1$
$Δ = {(- 4)}^{2} - 4 \times 1 \times 1$
$= 16 - 4 = 12$

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