Question

Find the discriminant of the following quadratic equations and hence determine the nature of the roots of the equation :
$x(x-5)=36$

Answer 1

$x(x-5)=36$

$\Rightarrow x^2-5x-36=0$

$D\equiv 5^2-4(-36)\left(1\right)=169=(13{)}^2$(i.e. perfect square)

Roots are real, distinct & rational.