Question

Find the discriminant of the following quadratic equations and hence determine the nature of the roots of the equation :
$x^2-2x-15=0$

Answer 1

Given equation: $x^2-2x-15=0$

$a=1,b=-2,c=-15$

$D=b^2-4ac$

$⟹D=(-2{)}^2-4(1\left)\right(-15)$

$⟹D=4+60$

$⟹D=64$

Thus $D>0$

$\therefore$ Roots are real and distinct.