Question

Find the discriminant of the following quadratic equations and hence determine the nature of the roots of the equation :
$x^2+x-3=0$

Answer 1

Given equation: $x^3+x-3=0$

$a=1,b=1,c=-3$

$D=b^2-4ac$

$⟹D=(1{)}^2-4(1\left)\right(-3)$

$⟹D=1+12$

$⟹D=13$

Thus $D>0$

$\therefore$ There are two distinct real zeros.