Question

Find the discriminant of the following quadratic equations and hence determine the nature of the roots of the equation :
$x^2=9$

Answer 1

Given equation: $x^2=9$

$⟹x^2-9=0$

$a=1,b=0,c=-9$

$D=b^2-4ac$

$⟹D=0-4\left(1\right)(-9)$

$⟹D=36$

Thus $D>0$

$\therefore$ There are two distinct real zeros.