Question

Find the discriminant of the following quadratic equations and hence determine the nature of the roots of the equation :
$3x^2-18x+27=0$

Answer 1

$3x^2-18x+27=0$

$D\equiv (18{)}^2-4(27\left)\right(3)$

$\equiv 324-320$

$\equiv 0$

$D=0\Rightarrow$ Roots are equal & also integers as b is divisible by 4$2a$