Question

Find the discriminant of the quadratic equation $32\sqrt{3}{x}^2+21x-\sqrt{3}=0$.

Answer 1

Given,

$32\sqrt{3}{x}^2+21x-\sqrt{3}=0$

$a=32\sqrt{3},b=21,c=-\sqrt{3}$

discriminant $D=b^2-4ac$

$=(21{)}^2-4(32\sqrt{3}\left)\right(-\sqrt{3})$

$=441+384$

$\therefore D=825$