Find the dispersive power of flint glass. The refractive indices of flint glass for red, yellow and violet lights are $1.613, 1.620$ and $1.632$ respectively.

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Solution

Given, $μ_{r} = 1.613; μ_{y} = 1.620; μ_{v} = 1.632$

The dispersive power is given by,

$ω = \frac{μ_{v} - μ_{r}}{μ_{y} - 1}$

$ω = \frac{1.632 - 1.613}{1.620 - 1} = \frac{0.019}{0.620} = 0.0306$

 Hence, $(C)$ is the correct answer.

Why this question ?
To test the basic understanding of the dispersive power.

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Find the dispersive power of flint glass. The refractive indices of flint glass for red, yellow and violet lights are 1.613, 1.620 and 1.632 respectively.

Find the dispersive power of flint glass. The refractive indices of flint glass for red, yellow and violet lights are $1.613, 1.620$ and $1.632$ respectively.