Find the distance between $(3, - 5)$ and $(- 4, 7)$

\sqrt{144}

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\sqrt{193}

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\sqrt{169}

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\sqrt{133}

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Solution

The correct option is B $\sqrt{193}$
Distance between two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ is $\sqrt{{(x_{2} - x_{1})}^{2} + {{(y}_{2} - y_{1})}^{2}}$
So, distance between $(3, - 5); (- 4, 7)$ is $\sqrt{{(- 4 - 3)}^{2} + {(7 + 5)}^{2}} = \sqrt{49 + 144} = \sqrt{193}$

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