Find the distance between $A (- 2, 7)$ and $B (- 5, 11)$ .

5

units

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4

units

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6

units

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8

units

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Solution

The correct option is A $5$ units
Distance between two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ can be calculated using the formula $\sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2}}$
Hence, AB $= \sqrt{{(- 5 + 2)}^{2} + {(11 - 7)}^{2}} = \sqrt{9 + 16} = \sqrt{25} = 5$

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Find the distance between A(−2,7) and B(−5,11).

The correct option is A 5 unitsDistance between two points (x1,y1) and (x2,y2) can be calculated using the formula √(x2−x1)2+(y2−y1)2Hence, AB =√(−5+2)2+(11−7)2=√9+16=√25=5

Find the distance between $A (- 2, 7)$ and $B (- 5, 11)$ .

The correct option is A $5$ units
Distance between two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ can be calculated using the formula $\sqrt{{(x_{2} - x_{1})}_{2}^{2} + {(y_{2} - y_{1})}_{2}^{2}}$
Hence, AB $= \sqrt{{(- 5 + 2)}^{2} + {(11 - 7)}^{2}} = \sqrt{9 + 16} = \sqrt{25} = 5$