Find the distance between -8 5 -2 and 2 5 -2

Distance AB=√((x_2 x_1)^2+(y_2 y_1)^2) ⇒ AB=√((25 85)^2+(2 2)^2) ⇒ AB=√((2+85)^2) ⇒ AB=105=2 units ...

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Byju's Answer

Standard X

Mathematics

Distance Formula

Find the dist...

Question

Find the distance between $(\frac{- 8}{5}, 2)$ and $(\frac{2}{5}, 2)$

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Solution

Distance $A B = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

$\Rightarrow A B = \sqrt{{(\frac{2}{5} - \frac{- 8}{5})}^{2} + {(2 - 2)}^{2}}$

$\Rightarrow A B = \sqrt{{(\frac{2 + 8}{5})}^{2}}$

$\Rightarrow A B = \frac{10}{5} = 2$ units

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Find the distance between (−85,2) and (25,2)

Distance AB=√(x2−x1)2+(y2−y1)2⇒AB=√(25−−85)2+(2−2)2⇒AB=√(2+85)2⇒AB=105=2units

Find the distance between $(\frac{- 8}{5}, 2)$ and $(\frac{2}{5}, 2)$

Distance $A B = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

$\Rightarrow A B = \sqrt{{(\frac{2}{5} - \frac{- 8}{5})}^{2} + {(2 - 2)}^{2}}$

$\Rightarrow A B = \sqrt{{(\frac{2 + 8}{5})}^{2}}$

$\Rightarrow A B = \frac{10}{5} = 2$ units