Find the distance between parallel lines $l (x + y) + p = 0$ and $l (x + y) - r = 0$

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Solution

t (x+y)+P=0
t(x+y)-r = 0 Dist, $d = ∣ ∣ ∣ \frac{P + r}{\sqrt{t^{2} + t^{2}}} ∣ ∣ ∣$
$d = \frac{1}{t \sqrt{2}} (P + r)$

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