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Question

Find the distance between the following pair of points.
(b+c,c+a) and (c+a,a+b).

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Solution

Distance between points (x1,y1) and (x2,y2) is (x1x2)2+(y1y2)2
Let P(b+c,c+a) and Q(c+a,a+b)
Then, distance between P and Q is
PQ=(c+a(b+c))2+(a+b(c+a))2PQ=(c+abc)2+(a+bca)2PQ=(ab)2+(bc)2PQ=a2+b22ab+b2+c22bcPQ=a2+2b2+c22ab2bc

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