Question

Find the distance between the following pairs of points $(2,8)$ and $(6,8)$.

Answer 1

We know that the distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is

$d=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$

Here, the given points are $(2,8)$ and $(6,8)$, therefore,

$d=\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}=\sqrt{{(6-2)}^2+{(8-8)}^2}=\sqrt{4^2+0^2}=\sqrt{16}=\sqrt{4^2}=4$

Hence, the distance is $4$ units.