Using distance formula if two points (x1,y1) and (x2,y2) are given.
d=√(x1−x2)2+(y1−y2)2
Part (A).
Given points are (2,3),(4,1)
Then distance d=√(x1−x2)2+(y1−y2)2
d=√(2−4)2+(3−1)2
=√(−2)2+(2)2
=√8Ans.
Part (B).
Given points are (−5,7),(−1,3)
Then distance d=√(x1−x2)2+(y1−y2)2
d=√(−5+1)2+(7−3)2
=√(−4)2+(4)2
=√32Ans.
Part (C).
Given points are (a,b),(−a,−b)
Then distance d=√(x1−x2)2+(y1−y2)2
d=√(a+a)2+(b+b)2
=√(2a)2+(2b)2
=√4(a2+b2)
=2√(a2+b2)Ans.