Find the distance between the points (2,3) and (5,7) in x-y plane.
A
2 units
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B
3 units
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C
4 units
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D
5 units
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Solution
The correct option is D 5 units The distance can be seen as the hypotense of the triangle. a = 5 - 2 = 3 units b = 7 - 3 = 4 units C =√a2+b2 =√(3)2+(4)2 C = 5 units