Find the distance between the points $(- 4, 0)$ and $(3, 0)$

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Solution

The points (-4, 0) and (3, 0) lies on the x-axis. Hence
$d = | x_{1} - x_{2} | = | 3 - (- 4) | = | 3 + 4 | = 7$
Aliter:
$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(3 + 4)^{2} + 0^{2}} = \sqrt{49} = 7$

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