Question

Find the distance between the points $(-4,0)$ and $(3,0)$

Answer 1

The points (-4, 0) and (3, 0) lies on the x-axis. Hence
$d=|x_1-x_2|=|3-(-4)|=|3+4|=7$
Aliter:
$d=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}=\sqrt{(3+4{)}^2+0^2}=\sqrt{49}=7$