Question

Find the distance between the points P(1 , -1) and Q(4 , -2).

• A. $2\text{units}$
• B. $3\text{units}$
• C. $\sqrt{10}\text{units}$
• D. $\sqrt{15}\text{units}$

Answer 1

The correct option is C $\sqrt{10}\text{units}$

According to the Distance Formula :
PQ =$\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}$
Here, $x_2=4,x_1=1,y_2=-2,y_1=-1$PQ = $\sqrt{(4-1{)}^2+(-2-(-1){)}^2}$
= $\sqrt{(3{)}^2+(-1{)}^2}$
= $\sqrt{9+1}$
= $\sqrt{10}\text{units}$