Find the distance between the points P(3,2) and Q(−2,−1).
Question 4 (iii)
Subtract 4p2q−3pq+5pq2−8p+7q−10from18−3p−11q+5pq−2pq2+5p2q.
The points (-2, 3), (6, 7) and (4, 1) are the vertices of triangle ABC. If P is the mid-point of AB and Q is the mid-point of AC, then, PQ = ?