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Question

Find the distance between the points whose position vectors are given as follows

2^i+3^j+5^k,7^i^k


A
314
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B
54
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C
319
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D
57
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Solution

The correct option is A 314
Distance Between two position vectors a^i+b^j+c^k and x^i+y^j+z^k is given by
(ax)2+(by)2+(cz)2
Given 2^i+3^j+5^k, 7^i^k
Distance =(27)2+(30)2+(5+1)2
=126
=314

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