Find the distance between the points whose position vectors are given as follows
−2^i+3^j+5^k,7^i−^k
A
3√14
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B
√54
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C
3√19
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D
√57
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Solution
The correct option is A3√14 Distance Between two position vectors a^i+b^j+c^k and x^i+y^j+z^k is given by √(a−x)2+(b−y)2+(c−z)2 Given −2^i+3^j+5^k, 7^i−^k Distance =√(−2−7)2+(3−0)2+(5+1)2 =√126 =3√14