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Question

Find the distance between two complex numbers z1=2+3i & z2=79i on the complex plane

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Solution

We have z1=2+3i and z2=79i.
This is equivalent to having two points in the plane, with coordinates (2,3) and (7,9)
Thus, distance between the two points is (27)2+(3+9)2=25+144=169=13

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