Find the distance between two complex numbers z1=2+3i & z2=7−9i on the complex plane
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Solution
We have z1=2+3i and z2=7−9i. This is equivalent to having two points in the plane, with coordinates (2,3) and (7,−9) Thus, distance between the two points is √(2−7)2+(3+9)2=√25+144=√169=13