Question

Find the distance between two parallel lines 5x +12y - 30 = 0 and 5x +12y-4=0

• A. 3
• B. 7
• C. $\frac{5}{2}$
• D. 2

Answer 1

The correct option is D 2

Putting y = 0 in 5x + 12y - 30 = 0, we get 5x - 30 = 0 or x = 6
$\therefore$ (6, 0) is a point on the first line 5x + 12 y - 30 = 0
Required distance between the parallel lines = Perpendicular distance of the point (6, 0) from the second line 5x + 12y - 4 = 0.
$=\frac{5.6+12.0-4}{\sqrt{5^2+{12}^2}}=\frac{30-4}{13}=2units$