Question

Find the distance between two points $(-4,3)and(0,0)$

Answer 1

The distance between two points $(X_1,Y_1)$&$(X_2,Y_2)$ in a plane is $S=\sqrt{{(X_2-X_1)}^2+{(Y_2-Y_1)}^2}$

Here $\left(X_{1,}{Y}_1\right)=(-4,3)$

and $\left(X_{2,}{Y}_2\right)=(0,0)$

So distance $S=\sqrt{{[0-(-4\left)\right]}^2+(0-3{)}^2}$

$$\begin{gathered} S=\sqrt{16+9} \\ S=5 \end{gathered}$$

Hence the distance between points $(-4,3)\&(0,0)$ is $5$units