Question

Find the distance from $\left(4,-2,6\right)$ to each of the following:

The $yz-$plane

Answer 1

To find the distance:

For the $yz-$plane, the $x-$coordinate is $0$.

So, the distance from the given point $\left(4,-2,6\right)$ to $yz-$plane is the $x-$coordinate.

Hence, the distance between the point $\left(4,-2,6\right)$ and the $yz-$plane is $\mathbf{4}$ units.