Find the distance of $(1, - 3)$ from the line $2 y - 3 x = 4$ .

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Solution

The distance of the point $P (1, - 3)$ from the line $2 y - 3 x - 4 = 0$ is the length of perpendicular from the point to the line which is given by
$∣ ∣ ∣ \frac{2 (- 3) - 3 - 4}{\sqrt{13}} ∣ ∣ ∣ = \sqrt{13} u n i t s$

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