Find the distance of the line $3 x + 4 y = 100$ from the origin.

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Solution

Distance of the line $3 x + 4 y = 100$ from the origin
$= \frac{| 3 \times 0 + 4 \times 0 - 100 |}{\sqrt{3^{2} + 4^{2}}}$
$= \frac{100}{5}$
$= 20$

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