Find the distance of the line 3x + 4y = 5 from the origin

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none of these

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Solution

The correct option is B 1
The distance d between the line $a x + b y + c = 0$ and point $(x_{1}, y_{1})$ is given by
$d = | \frac{a x_{1} + b y_{1} + c}{\sqrt{a^{2} + b^{2}}} |$
Therefore, Required distance $= | \frac{3 (0) + 4 (0) - 5}{\sqrt{3^{2} + 4^{2}}} | = \frac{5}{5} = 1$
Option D is correct

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