Question

Find the distance of the point (-1, 1) from the line 12(x + 6) = 5(y-2)

Answer 1

The given points is P(-1, 1) and the given line is 12x-5y+82 = 0

Let the required distance be d. Then,

d = length of perpendicular from P(-1, 1) on the line $12x-5y+82=0$

=$\frac{112\times (-1)-5\times 1+821}{\sqrt{{12}^2}+(-5{)}^2}=\frac{65}{\sqrt{1}69}$ = $\frac{65}{13}$ = 5 units