Find the distance of the point $P (1, - 3)$ from the line $2 y - 3 x = 4$ .

Open in App

Solution

$\begin{matrix} d i s t a n c e o f p o i n t (1, - 3) f r o m l i n e 2 y - 3 x = 4 - 3 x + 2 y - 4 = 0 d = \frac{| - 3 (1) + 2 (- 3) - 4 |}{\sqrt{9 + 4}} d = \frac{13}{\sqrt{13}} d = \sqrt{13} \end{matrix}$

Hence, this is the answer.

Suggest Corrections

Similar questions

(3, - 5)

3 x - 7 y - 4 = 0

(1, - 3)

2 y - 3 x = 4

3 x + 2 y - 5 z - 13 = 0

(5, 3, 4)

Find the distance of the point (2, 5) from the line 3 x + y + 4 = 0 measured parallel to a line having slope $3 / 4.$

Join BYJU'S Learning Program