Find the distance of the point $P (- 6, 8)$ from the origin.

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Solution

The distance of the point $P (- 6, 8)$ from the origin is $\sqrt{6^{2} + 8^{2}} = \sqrt{36 + 64} = \sqrt{100} = 10$ units.

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Similar questions

What is the distance of the point (-6,8) from the origin?

Find the distance of the point P from the origin:

The distance of the point P(-6, 8) from the origin is

(a) $8$ (b) $2 \sqrt{7}$ (c) $6$ (d) $10$

2 \sqrt{7}

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