Find the distance travelled with the following pairs of monomials as their speed and time respectively:
(i) (25a2b2,50b)
(ii) (12abc,23cde)
(iii)(5c2d2,4a2b2) [3 MARKS]
Concept: 1 Mark
Application: 2 Marks
Distance Travelled
=Speed×Time
(i) Distance Travelled =25a2b2×50b=1250a2b3
(ii) Distance Travelled =12abc×23cde=276abc2de
(iii) Distance Travelled =5c2d2×4a2b2=20a2b2c2d2