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Question

Find the divisor g(x), when the polynomial p(x)=4x3+2x210x+2 is divided by g(x) and the quotient and remainder obtained are (2x2+4x+1) and 5 respectively

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Solution

We know that the division algorithm states that:
Dividend=(Divisor×quotient)+Remainder

Here it is given that the dividend is p(x)=4x3+2x210x+2, the divisor is g(x), the quotient is 2x2+4x+1 and the remainder is 5, therefore,

4x3+2x210x+2=[g(x)(2x2+4x+1)]+5g(x)=4x3+2x210x+22x2+4x+1

The division is shown above.

Hence, from the above division, we get that the divisor is g(x)=2x3


634260_562442_ans_7151c405d7e54def98e1ff39bba18437.png

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