Question

Find the domain and range of
$f\left(x\right)=\frac{x^2-9}{x-3}$

Answer 1

$f\left(x\right)=\frac{x^2-9}{x-3}=\frac{\left(x-3\right)\left(x+3\right)}{\left(x-3\right)}=x+3$

$domainoff\left(x\right)isR-\left\{3\right\}becausefuncion$

$isnotdefinedatx=3$

${lim}_{x\to 3}f\left(x\right)=6$

$Rangeoff\left(x\right)isR-\left\{6\right\}$