Question

Find the domain of definition of the following function:
$y=\sqrt{\log (x+1)}.$

Answer 1

$y=\sqrt{log(x+1)}$

For $y$ to be real and defined,

$x+1$ must be $>0\Rightarrow x+1\ge 1\Rightarrow x\ge 0$

Domain of $y$ is $x\in [0,\infty ).$