Question

Find the domain of definition of the following function:
$y=\sqrt{{\sin }^{2}x-\sin x}$

Answer 1

${\sin }^2-\sin x\ge 0$

$\sin -(\sin x-1)\ge 0$

$\sin x\in (-\infty ,0)\cup (1,\infty ),x\in \left[\right(2n+1)\pi ,(2n+2\left)\pi \right].$