The correct option is D (2,3)
For given function to be defined,
(i) x2−5x+16>0 which is true for all x. Since discriminant of the quadratic is negative.
(ii) 1−log(x2−5x+16)>0⇒log(x2−5x+16)<1⇒x2−5x+16<101
⇒x2−5x+6<0⇒(x−2)(x−3)<0⇒x∈(2,3)
Considering above two we get required domain (2,3)