Find the domain of $g (x) = 1 / (x^{2} + 6)$

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Solution

Given function is $g (x) = \frac{1}{1 + x^{2}}$
Clearly for any real number $x$ , $1 + x^{2}$ which is the denominator
of given rational function can never be zero
Thus above function is defined for all real numbers
Hence domain is $(- \infty, \infty)$

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