Find the domain of real-valued function- f x -2 x -1- x -9 A- R -9B- RC- R -9D- R - -9

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Range, Domain and Codomain

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Question

Find the domain of real-valued function: $f (x) = \frac{2 x + 1}{x - 9}$

R - {9}

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R - {-9}

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R + {9}

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Solution

The correct option is A R - {9}
Domain of a real-valued function is set of values where function is defined.
Given: $f (x) = \frac{2 x + 1}{x - 9}$
The function is defined when denominator $\neq$ 0
$\Rightarrow x - 9 \neq 0$
$\Rightarrow x \neq 9$
Hence domain of $f (x)$ is all real values except 9 .i.e. $x \in R - {9}$

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Find the domain of real-valued function: f(x)=2x+1x−9

The correct option is A R - {9}Domain of a real-valued function is set of values where function is defined. Given: f(x)=2x+1x−9 The function is defined when denominator ≠ 0 ⇒x−9≠0 ⇒x≠9 Hence domain of f(x) is all real values except 9 .i.e. x∈R - {9}

Find the domain of real-valued function: $f (x) = \frac{2 x + 1}{x - 9}$