f(x)=cos−1√log[x]|x|x, where,[⋅] denotes the greatest integer function.
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Solution
Given, f(x)=cos−1√log[x]|x|x For given function to be defined [x]>0⇒x≥1 ∴|x|x=1 ⇒f(x)=cos−1√log[x] Also for square root to be defined log[x]≥0⇒[x]≥1⇒x≥1 And for cos−1 to be defined √log[x]≤1⇒log[x]≤1⇒[x]<e⇒x<3 Hence domain of f(x) is [1,3)