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Byju's Answer
Standard XII
Mathematics
Definition of Functions
Find the doma...
Question
Find the domain of the following function:
f
(
x
)
=
1
[
x
]
+
log
1
−
x
(
x
2
−
3
x
+
10
)
+
1
2
−
|
x
|
+
1
√
sec
(
sin
x
)
A
(
−
2
,
−
1
)
∪
(
−
1
,
0
)
∪
(
1
,
2
)
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B
(
−
2
,
−
1
)
∪
(
−
1
,
0
)
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C
(
−
2
,
−
1
)
∪
(
1
,
2
)
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D
(
−
1
,
0
)
∪
(
1
,
2
)
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Solution
The correct option is
A
(
−
2
,
−
1
)
∪
(
−
1
,
0
)
1
[
x
]
⇒
x
∉
[
0
,
1
)
and
log
1
−
x
(
x
2
−
3
x
+
10
)
x
2
−
3
x
+
10
>
⇒
x
∈
R
1
−
x
>
0
⇒
x
∈
R
2
−
x
≠
1
⇒
x
∉
1
and
2
−
∣
x
∣
=
0
⇒
∣
x
∣
−
2
=
0
⇒
x
≠
−
2
,
2
and
sec
(
sin
x
)
>
0
⇒
−
1
≤
sin
x
≤
1
⇒
x
∈
R
Hence domain is
x
∈
(
−
2
,
−
1
)
∪
(
−
1
,
0
)
Suggest Corrections
0
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